Question

Clair has 60 yd of fence with which to build a rectangular pig sty. What is the maximum area she can enclose?

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Answer 1

Answer: 225 is Correct just confirming

Explanation:

I just took the K 12 test

Answer 2

Answer: Maximum area would be 225 sq. yard.

Explanation:

Since we have given that

Perimeter of rectangular pig sty = 60 yd

As we know the formula for "Perimeter ":

`60=2(l+b)\\\\(60)/(2)=l+b\\\\30=l+b`

Since we need the maximum area she can enclose:

Square with same perimeter would enclose maximum area than the rectangle.

For this we assume l=b.

So, it becomes,

`30=l+l\\\\30=2l\\\\(30)/(2)=l\\\\15\ yd=l`

So, Maximum area would be

`Side* Side\\\\=Side^2\\\\=15^2\\\\=225\ sq.\ yard`

Hence, the maximum area would be 225 sq. yard.