Question

The expression -4.9t^2+50t + 2 represents the height, in meters, of a toy rocket t seconds after launch. The initial height of the rocket, in meters is...

Answer 1

we have that

H(t)=-4.9t²+50t + 2

we know that
The initial height of the rocket, in meters is for t=0 sec
fot t=0
H(t)=-4.9*0²+50*0 + 2------> H(t)=2 m

the answer is
The initial height of the rocket is 2 m