asked 203k views
0 votes
Factor. 8x5+4x2−12 4(2x5+x2−3) 4(2x5+4x2−12) 8(x5+4x2−12) 4x2(2x3+x−3)

asked
User RMP
by
7.4k points

2 Answers

1 vote

Answer:

B) 4(2
x^(5) +
x^(2) - 3)

answered
User Zsltg
by
7.5k points
6 votes

Answer:

Option (a) is correct.

The given polynomial
8x^5+4x^2-12 can be factorized as
4(2x^5+x^2-3)

Explanation:

Given : Polynomial
8x^5+4x^2-12

We have to factorize the given polynomial
8x^5+4x^2-12 and choose the correct out of given options.

Consider the given polynomial
8x^5+4x^2-12

Taking 4 common from each term, we have,


8x^5+4x^2-12=4(2x^5+x^2-3)

Since, we cannot factorize the expression
2x^5+x^2-3 further using any factorization technique.

So , the given polynomial
8x^5+4x^2-12 can be factorized as
4(2x^5+x^2-3)

Thus, Option (a) is correct.

answered
User Reckless
by
8.4k points
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