Question

Solve for f. d = 16ef² f=±4de‾‾‾√ f=±4de√e f=±de√4e f=±de√16

Answer 1

The value of f out of given expression
`d=16ef^2` is
`(\pm 1)/(4)\sqrt{(d)/(e)}`

Explanation:

Given : expression
`d=16ef^2`

We have to solve for f.

Consider the given expression
`d=16ef^2`

Divide both side by 16e, we get,

`(d)/(16e)=f^2`

Now, taking square root, both sides, we have,

`\sqrt{(d)/(16e)}=√(f^2)`

Simplify, we get,

`\sqrt{(d)/(16e)}=f`

We know
`√(16)=\pm 4` , we get,

`(\pm 1)/(4)\sqrt{(d)/(e)}=f`

Thus, The value of f out of given expression
`d=16ef^2` is
`(\pm 1)/(4)\sqrt{(d)/(e)}`

Answer 2

Answer:
`f=\pm (√(de))/(4e)`

Explanation:

Here, the given expression is,

`d=16ef^2`

or
`16ef^2=d`

`\implies f^2 =(d)/(16e)`

`\implies f=\pm\sqrt{(d)/(16e)}`

`\implies f =\pm (√(d))/(4√(e))`

`\implies f= \pm (√(de))/(4e)` ( By rationalization )

Which is the required value of f.