Question

What is the density (in g/l) of a gas with a molar mass of 146.06 g/mol at 1.03 atmosphere and 297 k

Answer 1

6.17

Step-by-step explanation:

:)

Answer 2

According to Ideal Gas Equation,

P V = n R T
Also,
n = mass / M.mass
So,
P V = (mass × R × T) ÷ M.mass
Or,
P × M.mass = (mass × R × T) ÷ V

Since,
Density = mass / volume
So,
P × M.mass = Density × R × T
Or,
Density = (P × M.mass) ÷ (R × T)
Putting Values,

Density = (1.03 atm × 146.06 g/mol) ÷ (0.0821 L.atm.mole⁻¹.K⁻¹ × 297 K)

Density = 6.16 g/L