Question

How many real solutions does the equation y2− 8y + 16 = 0 have?

A. 0
B. 1
C. 2
D. 3

Answer 1

We can solve this equation by completing the square. Notice that
`4*2=8` and
`4^(2)=16`. Therefore, we can turn
`y^(2)-8y+16=0` into
`(y-4)^(2)=0`. y, in this equation, only has one real solution: 4. So your answer would be (B).