When entering coefficients to balance equations, recall that just writing the symbol implies "1." Therefore, if a coefficient of "1" is required, choose &quo…

Question

When entering coefficients to balance equations, recall that just writing the symbol implies "1." Therefore, if a coefficient of "1" is required, choose "blank" for that box. Balance the following equation. 2C2H2 + O2→ 4CO2 + H2O

Answer 1

The Equation given in statement is as follow,

2 C₂H₂ + O₂ → 4 CO₂ + H₂O

According to equation,

Carbon atoms on reactant side are 4 in number, and that on product side are also 4 in number. SO, carbon atoms are balanced.

Hydrogen atoms on reactant side are 4, and on product side are 2. Means Hydrogen atoms are not balance. So, to balance them multiply H₂O with 2. So,
2 C₂H₂ + O₂ → 4 CO₂ + 2 H₂O

Now, calculate number of Oxygen atoms on both sides. There are 2 Oxygen atoms on reactant side and 10 Oxygen atoms on product side. So, to balance them multiply O₂ on reactant side with 5. So,

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

Above Equation is balanced.