asked 231k views
1 vote
a gas is contained in a thick walled balloon. when the pressure changes from 100 kpa to 90.0 kpa, the volume changes from 2.50 L to 3.75 L and the temperature changes from 303 K to _____ K

2 Answers

5 votes

Answer:

409 K

Step-by-step explanation:

answered
User Alex Shestakov
by
7.6k points
2 votes
Let's assume the gas is acting ideally, Then, applying Ideal Gas Equation, assuming number of moles constant,

P₁ V₁ / T₁ = P₂ V₂ / T₂ ------ (1)
Data:
P₁ = 100 kPa

P₂ = 90 kPa

V₁ = 2.50 L

V₂ = 3.75 L

T₁ = 303 K

T₂ = ?

Solving Eq. 1 for T₂,

T₂ = (P₂ × V₂ × T₁) × (P₁ × V₁)
Putting Values,
T₂ = (90 kPa × 3.75 L × 303 K) ÷ (100 kPa × 2.50 L)

T₂ = 409 K
answered
User Yanick Salzmann
by
7.8k points
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