Question

If 5.0 milliliters of a 0.20 M HCl solution is required to neutralize exactly 10. milliliters of NaOH, what is the concentration of the base?

Answer 1

Hello!

The neutralization equation of HCl and NaOH is the following:

HCl + NaOH → NaCl + H₂O

If 5 mL of 0,2 M HCl were required to neutralize exactly 10 mL of NaOH we can use the following equation (mole equivalency at equivalence point) to find the concentration of the base:


`moles NaOH=moles HCl \\ \\ C NaOH*VNaOH=C HCl * V HCl \\ \\ C NaOH= (CHCl*VHCl)/(V NaOH)= (0,2 M * 5 mL)/(10 mL)=0,1 M`

So the concentration of NaOH is 0,1 M

Have a nice day!