Question

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.

Complete the following proof.

Prove: The midpoint of the hypotenuse of a right triangle is equidistant from the three vertices.

Answer 1

For M:
M=(((0+a)/2), ((b+0)/2))=(((a)/2), ((b)/2))
For MB:
MB=root((a/2 - a)^2 +(b/2 - 0)^2)
MB=root((a/2 - a2/2)^2 +(b/2)^2)
MB=root((-a/2)^2 +(b/2)^2)
MB=root(a^2/4 + b^2/4)
For MC:
MC=root((a/2 - 0)^2 +(b/2 - b)^2)
MC=root((a/2)^2 +(b/2 - b2/2)^2)
MC=root((a/2)^2 +(-b/2)^2)
MC=root(a^2/4 + b^2/4)
For MA:
MA=root((a/2 - 0)^2 +(b/2 - 0)^2)
MA=root((a/2)^2 +(b/2)^2)
MA=root(a^2/4 + b^2/4)