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What is the mass in grams of 5.11 x 10^25 molecules of CaCO3? If possible can i get work shown I want to know the process of how its solved because I have various questions similar to this:) thanks

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mass of CaCo3 is calculated as follows

calculate the moles of CaCO3 by use of Avogadro constant
that is 1 moles = 6.02 x10^23 molecules

what about 5.11 x10^25 molecules

by cross multiplication

= 1 mole x ( 5.11 x10^25) /( 6.02 x10^23) = 84.88 moles

mass = mole x molar mass
the molar mass of CaCO3 = 40.078 + 12.011+ (3 x15.999) = 100.086 g/mol

mass is therefore = 84.88 moles x 100.086 g/mol= 8495.3 grams
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User Ali Navidi
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