Question

How do we get the answer?

Answer 1

`\frac{ {a}^( - 3) }{ {a}^(2).a}`

In the denominator as you can see that the bases are same, Therefore we're gonna add those powers.
something like this:

`= \frac{ {a}^( - 3) }{ {a}^(2 + 1) } \\ = \frac{ {a}^( - 3) }{ {a}^(3) }`

As we take the numerator to the denominator (when the base is same) then, the powers are turned to negative something like this:

`\frac{1}{ {x}^(3) } \\ = 1 * {x}^( -3) \\ = {x}^( - 3)`


So we'll do the same thing here,

`{a}^( - 3) * {a}^( - 3)`
Bases are same so once again add the powers,

`{a}^( (- 3 ) + (- 3))`

and you'll get :

`{a}^( - 6)`
which is the same thing as

`\frac{1}{ {a}^(6) }`