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What is the approximate solution to this equation? x³ = 65.5 x≈4 x≈5 x≈16 x≈21

What is the approximate solution to this equation? x³ = 65.5 x≈4 x≈5 x≈16 x≈21
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What is the approximate solution to this equation? x³ = 65.5 x≈4 x≈5 x≈16 x≈21

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User HellCatVN
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2 Answers

1 vote
I personally think that it =4
answered
User BubbleGuppies
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8.6k points
5 votes

\sqrt[3]{65.5} = \sqrt[3]{64} \text { (Nearest perfect cube)}


\sqrt[3]{64} = 4
answered
User Vjy
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8.7k points
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