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Find the horizontal or oblique asymptote of f(x) = negative 3 x squared plus 7 x plus 1, all over x minus 2

1 Answer

2 votes
When you perform the indicated division, you get

(-3x^2+7x+1)/(x-2)=-3x+1+(3)/(x-2)

The "quotient" part of this result is the oblique asymptote:
y = -3x +1
Find the horizontal or oblique asymptote of f(x) = negative 3 x squared plus 7 x plus-example-1
answered
User Bhabani Shankar
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7.8k points
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