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4 NH3 + 5 O2 --> 4 NO + 6 H2O If 824g of NH3 reacts with 256g of O2, how many grams of nitrogen monoxide will be produced?

4 NH3 + 5 O2 --> 4 NO + 6 H2O If 824g of NH3 reacts with 256g of O2, how many grams of nitrogen monoxide will be produced?
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4 NH3 + 5 O2 --> 4 NO + 6 H2O

If 824g of NH3 reacts with 256g of O2, how many grams of nitrogen monoxide will be produced?

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User Andrew Patton
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Answer:

4 NH3+5 02. 4 NO + 6 H2O(g) will produced 1158 grm

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User Nestoraj
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