Question

Find the equation of a line that contains the points (-2,-3 and. (0,4). Express the equation in a slope-intercept form.

Answer 1

Hey there!

Slope intercept form is defined as:

y = mx + b

Where m is the slope and b is the y intercept.

In order to find the slope, we can use the slope given two points formula:

y2-y1/x2-x1 = 4-(-3)/0-(-2) = 4 + 3/2 = 7/2

Now, we can plug in the x and y values, as well as the slope to find b. We'll use (-2, -3). We have:

-3 = 7/2(-2) + b
-3 = -14/2 + b
-3 = -7 + b
-3 + 7 = b
4 = b

Our equation is y = 7/2x + 4

Hope this helps!

Answer 2

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Find Slope :
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`\text { Slope = } (4+3)/(0+2) = (7)/(2)`

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Find y-intercept
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At (0, 4), y-intercept = 4

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Equation :
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`y = mx + b`


`y = (7)/(2) x + 4`