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How many roots does the polynomial function y=(x-8)(x+3)^2 have

2 Answers

6 votes

Answer: 2

Explanation:

answered
User Arets Paeglis
by
8.6k points
6 votes

Answer:

the given polynomial has two roots

Explanation:

the polynomial function y=(x-8)(x+3)^2

To find the number of roots we look at the exponent of each factor

(x-8) has exponent 1 , x=8 is a root (one root)

(x+3)^2 has exponent 2 , x=-3 is one of the root

(x+3)^2=0

take square root on both sides

x+3=0

x= -3

So the given polynomial has two roots 8 and -3

answered
User Krissie
by
8.4k points

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