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the pull of gravity on mars is 3.7m/s^2. if a astronaut on mars lifts a 10 kg rock 1 m off the ground, just to see whats under it, how much gravitational potential energy does the rock have?

2 Answers

5 votes

Final answer:

The gravitational potential energy of the rock is 37 J.

Step-by-step explanation:

The gravitational potential energy of an object is given by the formula:

PE = mgh

where:

  • PE is the potential energy
  • m is the mass of the object
  • g is the acceleration due to gravity
  • h is the height of the object

In this case, the mass of the rock is 10 kg and it is lifted 1 m off the ground on Mars where the acceleration due to gravity is 3.7 m/s². Therefore, the gravitational potential energy of the rock is:

PE = (10 kg) * (3.7 m/s²) * (1 m) = 37 J

answered
User Adrian Bigland
by
7.6k points
3 votes
Gravitational potential energy can be calculated using the formula:


PE_(grav) =mgh

Where:
PEgrav = Gravitational potential energy
m= mass
g = acceleration due to gravity
h = height

On Earth acceleration due to gravity is a constant 9.8 but since the scenario is on Mars, the pull of gravity is different. In this case, it is 3.7, so we will use that for g.

So put in what you know and solve for what you don't know.
m = 10kg
g = 3.7m/s^2
h = 1m

So we put that in and solve it.

PE_(grav) =mgh

PE_(grav) =(10kg)(3.7m/s^(2))(1m)

PE_(grav) =37J


answered
User Georgebrock
by
8.4k points