Question

Kx-3y=4

4x-5y=7
In the system of equations above, k is a constant and x and y are variables. For what value of k with a symptom of equation have no solution?

A)12/5
B)16/7
C)-16/7
D)-12/5

Answer 1

To solve this problem, you need to recognize that the ratios of the coefficients must be equal. So the ratio for this system would be k/4 = -3/-5. Solving for k we get k = (3)*(4)/5 = 12/5, hence the answer is A. Hope that helps!