Question

Zinc reacts with iodine in a synthesis reaction. write the balanced equation and determine the theoretical yield of a 125 g sample of zinc was used

Answer 1

`m_(ZnI_2)^(theoretical)=610.3gZnI_2`

Step-by-step explanation:

Hello,

In this case, the required chemical reaction is:

`Zn(s)+I_2(g) \rightarrow ZnI_2(s)`

In such a way, if 125 g react with sufficient iodine in stoichiometric proportions (no excess), the theoretical yield of zinc iodide turns out as shown below:

`m_(ZnI_2)^(theoretical)=125gZn*(1molZn)/( 65.38gZn)*(1molZnI_2)/(1molZn)*(319.22gZnI_2)/(1molZnI_2) \\m_(ZnI_2)^(theoretical)=610.3gZnI_2`

Considering that the molar ratio zinc to zinc iodide is 1 to 1.

Best regards.

Answer 2

The theoretical yield is calculated as follows


write the equation for reaction
that is 2 Zn + I2 ------> 2 znI

then find the moles of Zn used
moles= mass/molar mass
= 125/ 65.4 = 1.911moles

by use of mole ratio between Zn to Zni which is 2:2 the moles of ZnI is also= 1.911moles

theoretical yield is therefore= moles of ZnI x molar mass of znI


= 1.911 moles x 319.2 g/mol = 609.99 grams