As,
w/w % = weight of Solute / Weight of Solution × 100 --- (1)
Finding weight of Solute:
As,
1 mole of NaOH = 40 g
So,
18 moles = X g
Solving for X,
X = (18 mol × 40 g) ÷ 1 mol
X = 720 g
Finding mass of Solution:
Multiply density of the solution by 100 mL
So,
= 1.48 g/mL × 1000 mL
= 1480 g
Putting values in eq. 1,
w/w % = 720 g / 1480 × 100
w/w % = 48.64 %