Question

Unit 4 mid

Find the Perimeter of the triangle. Round 2 decimal places.

Answer 1

A (-2, 3) B(3, 0) C(-4,-3)


`\text {Length of AB = } √((-2-3)^2+ (3-0)^2)`


`\text {Length of AB = } √((-5)^2+ (3)^2)`


`\text {Length of AB = } √(25 + 9)`


`\text {Length of AB = } √(34)`


`\text {Length of AB = } 5.83`


`\text {Length of BC = } √((3+4)^2+ (0+3)^2)`


`\text {Length of BC = } √((7)^2+ (3)^2)`


`\text {Length of BC = } √(49 + 9)`


`\text {Length of BC = } √(58)`


`\text {Length of BC = } 7.62`


`\text {Length of AC = } √((-2+4)^2+ (3+3)^2)`


`\text {Length of AC = } √((2)^2+ (6)^2)`


`\text {Length of AC = } √(4 + 12)`


`\text {Length of AC = } √(16)`


`\text {Length of AC = } 4}`

Perimeter = 5.83 + 7.62 + 4 = 17.45 units