Question

Write the equation in standard form for the circle passing through ( - 6,0) centered at the origin.

Answer 1

The equation for a circle:


`\boxed { \boxed { (x - a)^2 + (y - b)^2 = r^2}}`

Since the centre is at (0,0), then the equation will be:


`\boxed { \boxed {x^2 + y^2 = r^2}}`

It passed through (-6, 0) :


`(-6)^2 + 0^2 = r^2`


`r^2 = 6^2`


`r = 6`

The radius is 6, therefore the equation of the circle is :


`x^2 + y^2 = 6^2`


`\boxed { \boxed { x^2 + y^2 = 36}}`