What is the [oh–] in a sample of lime juice with a ph of 2.0?

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asked Apr 11, 2019 184k views

1 Answer

Milan M · Answer 1 · 2019-04-17T20:05:31+0000

As we know,
pH + pOH = 14
Finding pOH,
pH + pOH = 14

2 + pOH = 14

pOH = 14 -12

pOH = 12

Concentration of [OH⁻] is calculate as,

pOH = -log [OH⁻]

12 = -log [OH⁻]

-12 = log [OH⁻]

[OH⁻] = 10⁻¹² Taking antilog

[OH⁻] = 1 × 10⁻¹²

What is the [oh–] in a sample of lime juice with a ph of 2.0?

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