A basketball player can leap upward 0.42 m. What is the magnitude of his initial velocity at the start of the leap? Use g=9.81 m/s2.

asked Dec 14, 2019 70.1k views

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by Hakro

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Farmula 2gh=vf²-vi²
2×0.42×9.81=0²-vi²
8.2404=vi²
Vi=✓8.2404
Vi=2.87m/sec

Yolenny answered Dec 20, 2019

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