Question

in these triangles, side AB is congruent to side DF, and side BC is congruent to side FG. Determine the values of x and y

Answer 1

I added a screenshot with the complete question

Answer:
x = 3
y = 9

Step-by-step explanation:
1- getting the value of x:
We are given that:
side AB is congruent to side DF. This means that:
AB = DF
3(2x+10) = 12x + 12
6x + 30 = 12x + 12
12x - 6x = 30 - 12
6x = 18
x = 18/6
x = 3

2- getting the value of y:
We are given that:
side BC is congruent to side FG. This means that:
BC = FG
2y + 12 = 2(2y-3)
2y + 12 = 4y - 6
4y - 2y = 12 + 6
2y = 18
y = 18/2
y = 9

Hope this helps :)