How many mL of a 4.50M NaBr solution are needed to make 250 mL of a 0.75M solution of NaBr?

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asked Sep 4, 2019 208k views

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Senne Verhaegen · Answer 1 · 2019-09-10T14:21:16+0000

M1V1=M2V2

(4.50)(x)=(0.75)(250)
(4.50)(x)=187.5
x=41.67 mL
You might want to double check the formula used, but as a chem student I’m confident this is right

How many mL of a 4.50M NaBr solution are needed to make 250 mL of a 0.75M solution of NaBr?

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