Question

Solve the system of equations y=2x y=x^2-3

Answer 1

if x = 3, y = 6
if x = -1, y = -2
hope it help :)

Answer 2

Explanation:

we can use the substitution method to solve this system of equations .

Substitute y= 2x in second equation y= x^2-3

we get

`2x=x^2-3\\x^2-2x-3=0`

Now factor the equation

`(x-3)(x+1)=0\\x-3=0 \\x+1=0`

We get

x=3 and x=-1

for x=3 y=2(3)=6

and for x=-1

y=2(-1)=-2

solution is

(3,6) and (-1,-2)