asked 224k views
5 votes
Given: ABCD is a trapezoid, AB = CD, BK ⊥ AD, AK = 10, KD = 20
Find: BC AD

asked
User Spagi
by
8.9k points

1 Answer

4 votes
AK=10; KD=20
AD=AK+KD
AD=10+20
AD=30

Like AB=CD this trapezoid is symmetric, then if we draw CL ⊥ AD:
LD=AK→LD=10
BC=KL=KD-LD=20-10→BC=10

Answers:
BC=10
AD=30
Given: ABCD is a trapezoid, AB = CD, BK ⊥ AD, AK = 10, KD = 20 Find: BC AD-example-1
answered
User ChancyWu
by
8.1k points

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