Question

A jar contains 6 red jelly beans, 4 green jelly beans, and 4 blue jelly beans.

If we choose a jelly bean, then another jelly bean without putting the first one back in the jar, what is the probability that the first jelly bean will be blue and the second will be blue as well?

Answer 1

6/91

Explanation:

khan

Answer 2

Total jelly beans = 6 + 4 + 4 = 14
Total blue jelly beans = 4

Probability = 4/14 x 3/13 = 6/91

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Answer: The probability of choosing two blue jelly is 6/91.
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