Question

Please a lot of points involved.

Answer 1

-2,6

Explanation:

Answer 2

To find points of intersection, we need to use simultaneous equations.

y = 2x --- 1
y =
`x^(2)` - 3 --- 2

Sub 1 into 2,

2x =
`x^(2)` - 3
0 =
`x^(2)` - 2x - 3

`x^(2)` - 2x - 3 = 0

Factorise,

(x - 3)(x + 1) = 0

Let each bracket equal to 0,

x - 3 = 0 x + 1 = 0
x = 3 x = -1

Sub 3 into equation 1,

y = 2(3)
= 6

Now sub -1 into equation 1,

y = 2(-1)
= -2

Therefore, your two y values are -2 and 6

Hope this helped! Ask me if there's any part of the working you don't understand :)