Question

(2y) to the power of -4 over (3y) to the power of -2

Answer 1

`\frac{ {2y}^(- 4) }{ {3y}^( - 2) }`
Which can be rewrote as


`\frac{1}{ {2y}^( 4) } / \frac{1}{ {3y}^(2) }`

There fore

`\frac{1}{ {2y}^( 4) } * \frac{ {3y}^(2) }{ 1} = \frac{ {3y}^(2) }{ {2y}^4 }`