the question in English is
Find the lesser of three consecutive numbers, if the sum of half of the smaller number plus one third of the larger number exceeds five to the number in between
Let
x---------> the smaller number
x+1------> the number in between
x+2-----> the larger number
we know that
(1/2)*x+(1/3)*(x+2)=(x+2)+5
so
(x/2)+(x/3)+(2/3)=x+7
(3x+2x-6x)/6=(21-2)/3
-3x=114
x=-38
therefore
the smaller number-------> x------> -38
the number in between------> x+1-----> -38+1-----> -37
the larger number-------------> x+2-----> -38+2----> -36
the answer is
the lesser of three consecutive numbers is -38
The answer in Spanish
Hagamos
x---------> el menor numero
x+1------> el numero del medio
x+2-----> el numero mayor
Conocemos lo siguiente
(1/2)*x+(1/3)*(x+2)=(x+2)+5
por lo tanto
desarrollando la ecuacion
(x/2)+(x/3)+(2/3)=x+7
(3x+2x-6x)/6=(21-2)/3
-3x=114
x=-38
nos queda que
el menor numero es -------> x------> -38
el numero del medio es ------> x+1-----> -38+1-----> -37
el numero mayor es -------------> x+2-----> -38+2----> -36
La respuesta es
El menor de los tres numero consecutivos es -38