Question

Find the 76th term of the arithmetic sequences 16 14 12

Answer 1

a₇₆ = - 134

Explanation:

The n th term of an arithmetic sequence is

`a_(n)` = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 16 and d = a₂ - a₁ = 14 - 16 = - 2, then

a₇₆ = 16 + (75 × - 2) = 16 - 150 = - 134