Question

I am stuck... Chemistry is the worst and anything is appreciated!

Answer 1

I think it is 110 mL but I’m not totally sure.

Answer 2

2.78 mL of solution will be needed to make 4.5 M solution with 0.50 grams of NaOH.

Step-by-step explanation:

Moles of sodium hydroxide = n

`n=(0.50 g)/(40 g/mol)=0.0125 mol`

`Moles (n)=Molarity(M)* Volume (L)`

Volume of sodium hydroxide solution =V

Molarity of the sodium nitrate solution = 4.5 M

`V=(0.0125 mol)/(4.5 M)=0.00278 L`

V = 0.00278 L = 2.78 mL

2.78 mL of solution will be needed to make 4.5 M solution with 0.50 grams of NaOH.