Question

In the equation above,a,b, and c are constants. If the equation is true for all values of x, what is the value of b?

Answer 1

b=19

Explanation:

We are given that an equation

`2x(3x+5)+3(3x+5)=ax^2+bx+c`

Given that the equation is true for all x

We have to find the value of b

`2x(3x+5)+3(3x+5)=ax^2+bx+c`

`6x^2+10x+9x+15=ax^2+bx+c`

`6x^2+19x+15=ax^2+bx+c`

Comparing coefficients of
`x^2` xand constant value on both side then we get

`a=6,b=19,c=15`

Hence, the value of b=19