(y 3 - 4y 2 + 7y - 6) (y - 2)

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asked Sep 15, 2019 102k views

1 Answer

Brahmana · Answer 1 · 2019-09-19T16:52:47+0000

y^4-4y^3+7y^2-6y-2y^3+8y^2-14y+12=
y^4-6y^3+15y^2-20y+12

or

y^3-4y^2+7y-6=y^3-4y^2+4y+3y-6=
y(y^2-4y+4)+3(y-2)=
y(y-2)^2+3(y-2)=(y-2)[y(y-2)+3]=(y-2)(y^2-2y+3)

(y^3-4y^2+7y-6)(y-2)=(y-2)^2(y^2-2y+3)

(y 3 - 4y 2 + 7y - 6) (y - 2)

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