Write z=-6+6i in polar form

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asked Jul 6, 2019 50.4k views

1 Answer

Hisham Hijjawi · Answer 1 · 2019-07-12T11:42:56+0000

z=r(cosα +i*sinα)
r=√(6²+6²)=√(36+36)=√(2*36)=6√2
tanα=6/-6=-1, α=135⁰, or α=3π/4 (if you need in π)

z=6√2(cos 135+i*sin 135)
or
z=6√2(cos 3π/4+i*sin 3π/4)

Write z=-6+6i in polar form

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