Hey there :)
We are given the coordinates ( 0 , 0 )
We are asked if this is a solution to the following:
y ≤ x² - 4
y > 2x - 1
Since we know the coordinates just substitute it as a value for x and y to check
1) y ≤ x² - 4
0 ≤ 0² - 4
0 ≤ - 4
( 0 , 0 ) is not a solution for this system since - 4 is not greater or equal to 0
2) y > 2x - 1
0 > 2(0) - 1
0 > - 1
( 0 , 0 ) is a solution for this system because - 1 is less than 0
Your final answer will be
D) No, ( 0 ,0 ) satisfies y > 2x - 1 but does not satisfy y≤ x² - 4