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A skier travels 12.0 m/s reaches the foot of a steady upward 18° incline and glides 18.2m up along this slope before coming to rest. What was the average coefficient of friction…

A skier travels 12.0 m/s reaches the foot of a steady upward 18° incline and glides 18.2m up along this slope before coming to rest. What was the average coefficient of friction…
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A skier travels 12.0 m/s reaches the foot of a steady upward 18° incline and glides 18.2m up along this slope before coming to rest. What was the average coefficient of friction?

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User Moritz Schmidt
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1 Answer

6 votes
Hi! :)

initial KE = work done on gravity + workdone on friction

1/2 m 12^2 = mgh/sin18 + mu*mg*sin18*h/sin18

72 = gh/sin18 + mu*g*h

we know h = 18.2/sin18

3.108
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User Ankit Dhadse
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