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How many molecules of CaCL2 are equivalent to 75.9g CaCl2

How many molecules of CaCL2 are equivalent to 75.9g CaCl2
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How many molecules of CaCL2 are equivalent to 75.9g CaCl2

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User Auroranil
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The answer is around 4.12x10^23 molecules 
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User Seeker
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User Themasterhimself
asked Jul 27, 2021 145k views
How many molecules of CaCl2 are equivalent to 75.9g CaCl2 (Ca=40.08g/mol, CL=35.45g/mol)
Themasterhimself asked Jul 27, 2021
by Themasterhimself
7.9k points
1 answer
5 votes
145k views
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