Question

Which is a zero od the quadratic function f(x)=16x²+32x-9?

Answer 1

Olá!


`\left[\begin{array}{ccc}\Delta=b^2-4.ac\\ \\ x=(-b\±√(\Delta))/(2.a)\end{array}\right]`

a = 16
b = 32
c = -9


`\Delta` = 32² - 4.16. (- 9)

`\Delta` = 1024 - (- 576)

`\Delta` = 1600


`x'=(-(32)+√(1600))/(2.16)=(-(32)+40)/(32)=(8)/(32)=0.25\\ \\ \\ x'' =(-(32)-√(1600))/(2.16)=(-(32)-40)/(32)=(-72)/(32)=-2.25`