Question

A gas sample occupies a volume of 0.923 l at a temperature of 25 c what is the charles's law constant for this sample including units

Answer 1

The volume of the gas is
`V=0.923 L=0.923 \cdot 10^(-3) m^3`
The temperature of the gas is
`T=25^(\circ)C + 273 = 298 K`

Charle's law can be written as:

`(V)/(T) =k`
So, by using the values of V and T, we can find the value of k, the Charle's law constant:

`k=(0.923 \cdot 10^(-3) m^3)/(298 K)=3.10 \cdot 10^(-6) m^3 K^(-1)`