Question

I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct

Answer 1

*If you need me to do #5, DM me!

3. The area of a triangle can be given by (just plug and chug as always):

`A_t = (1)/(2) bh = (1)/(2)(3)(4) = 6ft^2`
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):

`A_t = (1)/(2) bh = (1)/(2)(8)(3) = 12m^2`

`A_r = bh = 12(8) = 96m^2`
Now we just add them:

`96+12 = 108m^2`

So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:

`A_t = (1)/(2)bh`
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:

`A_t = (1)/(2)bh = (1)/(2)(2.5)(5) = 6.25cm^2`
Multiply by 4 to get total area:

`6.25*4 = 25cm^2`

So, the area of the given rhombus is 25cm².