Question

At an amusement park, the probability that a child eats popcorn and cotton candy is 0.48. the probability that a child eats popcorn is 0.79, and the probability that a child eats cotton candy is 0.83. what is the probability (rounded to the nearest hundredth) that a child eats cotton candy given that the child has already eaten popcorn? hint: cap p left parenthesis cap a vertical line cap b right parenthesis equals start fraction cap p left parenthesis cap a intersection cap b right parenthesis over cap p left parenthesis cap b right parenthesis end fraction 0.38 0.58 0.40 0.61

Answer 1

The probability is 0.58.

The probability of one event given another is given by:

P(A|B) = P(A and B)/P(A)

Let C = cotton candy and P = popcorn. For our question we have:

P(C|P) = P(C and P)/P(C) = 0.48/0.83 = 0.58