Question

A ball is thrown vertically upward.After t seconds its height(in feet)is given by the function h(t)=84t=16t^2.What is the maximum height that the ball will reach

Answer 1

The maximum height that the ball will reach is 220.5 feet.

Step-by-step explanation:

The ball reaches its maximum height when its velocity becomes zero. This happens at the highest point of the ball's trajectory. To find the maximum height, we can use the equation h(t) = 84t - 16t^2. The maximum height is attained when the ball is at its peak, so we need to find the value of t that corresponds to this point.

Since the equation is quadratic, we can find the maximum value of t by finding the axis of symmetry. The formula for the axis of symmetry of a quadratic function in the form ax^2 + bx + c is x = -b/2a.

In this case, a = -16 and b = 84. Plugging these values into the formula, we get t = -84 / (2 * -16) = 2.625.

To find the maximum height, we can substitute this value of t back into the equation h(t). h(2.625) = 84(2.625) - 16(2.625)^2 = 220.5 feet.

Answer 2

21 seconds!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!