The graph of f(x) = x3 + 6x2 + 12x + 8 is shown. Based on the graph, how many real number solutions does the equation x3 + 6x2 + 12x + 8 = 0 have?

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asked Apr 25, 2019 4.9k views

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RRStoyanov · Answer 1 · 2019-04-30T04:12:03+0000

You didn't show the graph.
Anyway, that equation is a perfect cube and equals
(x +2)^3
or (x +) * (x +) * (x +)
Therefore, it has 3 real number solutions and ALL of those solutions equal -2

The graph of f(x) = x3 + 6x2 + 12x + 8 is shown. Based on the graph, how many real number solutions does the equation x3 + 6x2 + 12x + 8 = 0 have?

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