Question

At 1:30 PM Tom leaves his boat from a dock and head south. He travels at a rate of 25 mph. 10 minuets later, Mary leaves the same dock in her speedboat and heads after Tom. If she travels at a rate of 30 mph, when will she catch up with Tom?

Answer 1

she will catch up with Tom after:

t = 1 hour

Explanation:

Answer 2

We write the cinematic equation for each case.
We have then:
For tom:
r = 25t
For Mary
r = 30 (t- (10/60))
We observe that we have a system of two equations with two unknowns.
Solving for t we have:
t = 1 hour
Answer:
she will catch up with Tom after:
t = 1 hour