Question

How do I get EF in question 12

Answer 1

check the picture below.

since the arcEF is 75°, then the central angle it is in is also 75°, and the radius is of course 2.4,


`\bf \textit{arc's length}\\\\ s=\cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\ ------\\ r=2.4\\ \theta =75 \end{cases}\implies s=\cfrac{(75)(\pi )(2.4)}{180}\implies s=\pi`