Question

If z is a standard normal variable, find the probability that z lies between -2.41 and 0

Answer 1

It is about 0.49202 or 49.2%.

Answer 2

Answer: 0.4920238

Explanation:

Given: z is a standard normal variable.

We know that probability of z lies lies between two values a and b is given by :-

`P(a<z<b)=P(z<b)-P(z<a)`

Now, the probability that z lies between -2.41 and 0 is given by :-

`P(-2.41<z<0)=P(z<0)-P(z<-2.41)\\\\\Rightarrow\ P(-2.41<z<0)=0.5-0.0079762=0.4920238` [By using z-table for standard normal distribution]

Hence, the probability that z lies between -2.41 and 0 = 0.4920238